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Question

asked Jan 15, 2022 147k views

1 Answer

Richard Skinner · Answer 1 · 2022-01-19T15:52:44+0000

Answer:

the vertical component of the force is 43.30 N.

Step-by-step explanation:

Given;

angle of inclination of the force, θ = 60⁰

magnitude of the force, F = 50 N

The vertical component of the force is calculated as follows;

$F_y = F * sin(\theta}\\\\F_y = 50 N * sin(60)\\\\F_y = 50 N * (√(3) )/(2) \\\\F_y = 25√(3) \ N\\\\F_y = 43.30 \ N$

Therefore, the vertical component of the force is 43.30 N.