Question

Plz answer fast need your help plz plz plz​

Answer 1

the vertical component of the force is 43.30 N.

Step-by-step explanation:

Given;

angle of inclination of the force, θ = 60⁰

magnitude of the force, F = 50 N

The vertical component of the force is calculated as follows;

`F_y = F * sin(\theta}\\\\F_y = 50 N * sin(60)\\\\F_y = 50 N * (√(3) )/(2) \\\\F_y = 25√(3) \ N\\\\F_y = 43.30 \ N`

Therefore, the vertical component of the force is 43.30 N.