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Net ionic equation for sodium carbonate and sulfuric acids?

Net ionic equation for sodium carbonate and sulfuric acids?-example-1

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Answer:

CO₃²¯(aq) + 2H⁺(aq —> H₂O(l) + CO₂(g)

Step-by-step explanation:

The net ionic equation for sodium carbonate (Na₂CO₃) and sulfuric acid (H₂SO₄) can be obtained as follow:

Na₂CO₃ + H₂SO₄ —>

In solution, Na₂CO₃ and H₂SO₄ will dissociate as follow:

Na₂CO₃(aq) —> 2Na⁺(aq) + CO₃²¯(aq)

H₂SO₄(aq) —> 2H⁺(aq) + SO₄²¯(aq)

Na₂CO₃(aq) + H₂SO₄(aq) —>

2Na⁺(aq) + CO₃²¯(aq) + 2H⁺(aq) + SO₄²¯(aq) —> 2Na⁺(aq) + SO₄²¯(aq) + H₂O(l) + CO₂(g)

Cancel out the spectator ions (i.e Na⁺ and SO₄²¯) to obtain the net ionic equation.

CO₃²¯(aq) + 2H⁺(aq —> H₂O(l) + CO₂(g)

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