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Megan's age is three years more than four times her daughter's age. If Megan's daughter's age is $d$ , Megan's age is

User Raupach
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1 Answer

5 votes

Answer: 4d + 3

Explanation:

Megan's daughter's age = d

Based on the information given, since Megan's age is three years more than four times her daughter's age, this can be written mathematically as:

= (4 × d) + 3

= 4d + 3

Therefore, Megan's age is 4d + 3.

For example, if the daughters age is 7 years, Megan's age will be:

= 4d + 3

= 4(7) + 3

= 28 + 3

= 31 years

User Zbug
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