1/3 ln(x) + ln(2) - ln(3) = 3
Recall that
, so
ln(x ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:
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Then
ln(2/3 x ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant e. (I'm using exp(x) = e ˣ so I can write it all in one line.)
exp(ln(2/3 x ¹ʹ³)) = exp(3)
Now exp(ln(x)) = x for all x, so this simplifies to
2/3 x ¹ʹ³ = exp(3)
Now solve for x. Multiply both sides by 3/2 :
3/2 × 2/3 x ¹ʹ³ = 3/2 exp(3)
x ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(x ¹ʹ³)³ = (3/2 exp(3))³
x = 3³/2³ exp(3×3)
x = 27/8 exp(9)
which is the same as
x = 27/8 e ⁹