Question

The volume of a gas is 550 mL at 960 mm Hg and 200.0 C. What volume

would the pressure of the gas be 830 mm Hg if the temperature is reduced

to 150.0C? Make sure your answer is rounded to nearest whole number

and your final answer has the units of mL. *

Answer 1

The volume will be 568.89 mL.

Step-by-step explanation:

Boyle's law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or P * V = k

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. That is, the pressure of the gas is directly proportional to its temperature. Gay-Lussac's law can be expressed mathematically as follows:

`(P)/(T)=k`

Where P = pressure, T = temperature, K = Constant

Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

`(V)/(T)=k`

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

`(P*V)/(T) =k`

Studying an initial state 1 and a final state 2, it is fulfilled:

`(P1*V1)/(T1) =(P2*V2)/(T2)`

In this case:

• P1= 960 mmHg
• V1= 550 mL
• T1= 200 C= 473 K (being 0 C=273 K)
• P2= 830 mmHg
• V2= ?
• T2= 150 C= 423 K

Replacing:

`(960 mmHg*550 mL)/(473K) =(830 mmHg*V2)/(423 K)`

Solving:

`V2=(423 K)/(830 mmHg) *(960 mmHg*550 mL)/(473K)`

V2= 568.9 mL

The volume will be 568.89 mL.