Question

What is the specific heat of a metal (in J/g℃) that weighs 150 g and absorbs 1.2 kJ (or 1,200 J) of heat when the temperature rises by 50.0℃?

Answer 1

0.16 J/g℃

Step-by-step explanation:

We have the following data:

heat = 1,200 J

mass of metal = m = 150 g

change in temperature = ΔT = 50.0℃

The heat absorbed is calculated by using the following equation:

heat = m x Cp x ΔT

So, we introduce the data in the equation to calculate the specific heat of the metal (Cp), as follows:

Cp = heat/(m x ΔT) = (1,200 J)/(150 g x 50.0℃) = 0.16 J/g℃