Question

What is the arc measure, in degrees, of ADC on circle P below?

70°


104°

Answer 1

The answer is "
`\overarc{ADC} = m\angle CPD + m\angle DPA = 186`"

Explanation:

Please find the image of the question:

In the circle p:

`\to m\angle APB + m\angle BPC + m\angle CPD + m\angle DPA = 360^(\circ) \\\\\to 70 + 104 + m\angle CPD + m\angle DPA = 360\\\\\to m\angle CPD + m\angle DPA = 360 - 70 - 104 = 186`

Let P is in the center

`\to` arc AD=
`m\angle APD`

`\to` arc DC =
`m\angle CPD`

`\to` arc BC =
`m\angle BPC`

arc AB =

When D is on arc AC:

`\to`arc ADC = arc AD + arc DC

`\to`arc ADC =
`m \angle CPD + m\angle DPA = 186`