Question

What is the amount of moles of NaOH, if the solution molarity is .33 M NaOH in 0.75 L solution

Answer 1

0.248 moles of NaOH

Step-by-step explanation:

Concept of Molarity is mol/L

[x] = 1 M

1 mol of x contained in 1 L of solution. We write molar concentrations between []

M = mol/L then M . L = mol

Our solution is NaOH

0.33 M . 0.75L = mol

This solution contains 0.248 moles of NaOH

Answer 2

The amount of moles of NaOH is 0.0495

Step-by-step explanation:

Molarity is a measure of concentration that is defined as the number of moles of solute that are dissolved in a given volume.

In symbolic form molarity is presented as:

`Molarity=(number of moles of solute)/(volume)`

Molarity is expressed in units
`(moles)/(liter)`.

In this case:

• Molarity= 0.33 M
• Number of moles of solute= ?
• Volume= 0.75 L

Replacing in the definition of molarity:

`0.33 M=(number of moles of solute)/(0.75 L)`

number of moles of solute= 0.33 M* 0.75 L

number of moles of solute= 0.0495 moles

The amount of moles of NaOH is 0.0495