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Find the z value to the right of the mean so that 69.85% of the area under the distribution curve lies to the left of it.

Please explain!

User FSCKur
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P(x < a) = 0.6985

Z score at p = 0.6985 using excel = NORM.S.INV(0.6985) = 0.5201

Find the z value to the right of the mean so that 69.85% of the area under the distribution-example-1
User Stracktracer
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