Calculate the molarity of 0.060 moles of sodium bicarbonate (NaHCO3) in 1500. mL of solution.

asked Jul 11, 2022 197k views

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Answer: 0.040 mol/l

Explanation: Molarity c = n/V (Concentration)

c = 0.060 mol / 1,5 l = 0,040 mol/l

Jahnette answered Jul 16, 2022

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