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Solve the triangle
a
b
c
d

Solve the triangle a b c d-example-1
User Rostyk
by
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1 Answer

0 votes

Answer:

B

Explanation:

Use the Law of Cosines to find the measure of segment c:


c=√(a^2+b^2-2ab*cos(C))\\\\c=√(12^2+13^2-2(12)(13)*cos(134))\\\\c=√(313-312cos(134))\\\\c=√(313-312(-.6946583705))\\\\c=√(313-(-216.7334116))\\\\c=√(313+216.7334116)\\\\c=√(529.7334116)\\

c ≈ 23.01593821 km ≈ 23 km

Since c = 23 km, our only options are choices B and D. Now, let's find the measure of angle A to confirm. To do this we will use the Law of Sines:


(sin(A))/(a) =(sin(C))/(c) \\\\(sin(A))/(12)=(sin(134))/(23.01593821)\\\\sin(A)=12((sin(134))/(23.01593821))\\\\A=sin^(-1)[12((sin(134))/(23.01593821))]\\\\

A ≈ 22.02726885° ≈ 22°

Since the measure of c = 23 km and the measure of angle A = 22°, the answer must be choice B.

User Gaspare Bonventre
by
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