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How do you solve 2x-3y=-4 and x=7-3y by substitution?

1 Answer

7 votes

Answer:


(1, 2)

Explanation:

We can solve this system using substitution.

In this case, we can substitute 7-3y for x, as they are of equal value.

Therefore...


2x-3y=-4\\2(7-3y)-3y=-4\\14-6y-3y=-4\\14-9y=-4

Subtract 14 from both sides:


-9y=-18

Divide both sides by -9


y=2

Now, substitute 2 for y to solve for x:


x=7-3y=7-3(2)=7-6=1

Therefore the solution to this system of equations is:


(x, y)=(1, 2)

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