Question

When 28242 J are transferred to water sample, its temperature increases 18⁰C to 63⁰C. Determine the mass of the water sample.

Answer 1

149.79

Step-by-step explanation:

Formula

Joules = m * c * delta (t)

Givens

J = 28242

m = ?

c = 4.19

Δt = 63 - 18 = 45

Solution

28242 = m * 4.19 * 45

28242 = m * 188.55

m = 28242 / 188.55

m = 149.79