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Which rule describes the composition of transformations that maps triangle BCD to triangle B""C""D""?

1 Answer

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Answer:

(d)

Explanation:

Given

See attachment for
\triangle BCD and
\triangle B

Required

The transformations

Using B and B"" as points of reference, we have:


B = (1,4)


B

The transformation is as follows:

First, reflect across y axis.

The rule is:


(x,y) \to (-x,y)

So, we have:


B(1,4) \to B'(-1,4)

Next, translate 6 units right.

The rule is:


(x,y) \to (x + 6,y)

So, we have:


B' (-1,4) \to B


B' (-1,4) \to B

Lastly, translate 5 units down

The rule is:


(x,y) \to (x,y-5)

So, we have:


B


B

Hence; (d) is correct

Which rule describes the composition of transformations that maps triangle BCD to-example-1
User Viktor Nonov
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