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Martin is playing a probability game with his friend. He places 9 blue marbles, 8 red marbles, and 3 white marbles in a

bag. What is the probability that Martin picks out a red marble, places it in his pocket, and picks out a second red
marble? Enter your answer as a fraction in the box provided.

User Magen
by
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2 Answers

3 votes

Final answer:

The probability of picking out a red marble, placing it in his pocket, and then picking out a second red marble is 28/95.

Step-by-step explanation:

The probability of picking out a red marble, placing it in his pocket, and then picking out a second red marble can be calculated as follows:

First, we need to find the probability of picking a red marble on the first draw. There are a total of 20 marbles in the bag (9 blue + 8 red + 3 white), and 8 of them are red. Therefore, the probability of picking a red marble on the first draw is 8/20.

After placing the first red marble in his pocket, there are now 19 marbles left in the bag. Out of these 19 marbles, 7 are red. Therefore, the probability of picking a second red marble is 7/19.

To find the probability of both of these events happening, we multiply the individual probabilities: (8/20) * (7/19) = 28/95.

User Kirk Broadhurst
by
8.1k points
2 votes

8/8 6/8 so your going to take 2 from 8/8 so that would be 6/8

User Kevin Bond
by
9.0k points

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