34.9k views
14 votes
Scores on a test are normally distributed with a mean of 63.2 and a standard deviation of 11.7. Find
P_(81) , which separates the bottom 81% from the top 19%.

User Ed Manet
by
8.2k points

1 Answer

12 votes

P81 = Mean + z * Standard deviation , Where Z is critical value at 81% confidence level.

= 63.2 + 0.8779 * 11.7 ( Z critical value calculated from Z table)

= 73.47

User Justin Pearce
by
7.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories