Question

A birthday balloon is filled with 6.4 L of Helium. The pressure changes to 0.87 atm and the balloon expands to occupy a volume of 20.5 L. What was the initial pressure exerted on the balloon in psi?

PLS HELP WITH WORK!!

Answer 1

3.97 psi

Step-by-step explanation:

Answer 2

3.97 psi

Step-by-step explanation:

The new pressure can be found by using the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

Since we're finding the new pressure

`P_2 = (P_1V_1)/(V_2) \\`

We have

`P_2 = (6.4 * 0.87)/(20.5) = (5.568)/(20.5) \\ = 0.2716.... \\ \\ = 0.27 \: \: \: atm`

But

1 atm = 14.7 psi

Then 0.27 atm =

`(14.7 * 0.27)/(1) = 3.969 \\`

We have the final answer as

3.97 psi

Hope this helps you