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A candle is placed 50 cm from a diverging lens with a focal length of 28. What is the image distance in cm.

User Jay Allard
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1 Answer

6 votes

Answer:

v = -17.94 cm

Step-by-step explanation:

Given that,

The candle is placed at a distance of 50 cm, u = -50 cm

The focal length of the diverging lens, f = -28 cm (negative in case of a concave lens)

We need to find the image distance. We know that the lens formula is as follows:


(1)/(v)-(1)/(u)=(1)/(f)\\\\(1)/(v)=(1)/(f)+(1)/(u)\\\\(1)/(v)=(1)/((-28))+(1)/((-50))\\\\v=-17.94\ cm

So, the image distance is equal to 17.94 cm.

User Incredible
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