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Find dy/dx in the following
1) y=x^[10] +10^[x] +e^[x]
2) y=㏒ x +e^[x]+√x - 1/x

User Sunil Rk
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1 Answer

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1. in picture 1

2. in picture 2

Hope this helps :T

Also I am not so shure about 2, but I am 98% shure 1 is right.

Find dy/dx in the following 1) y=x^[10] +10^[x] +e^[x] 2) y=㏒ x +e^[x]+√x - 1/x-example-1
Find dy/dx in the following 1) y=x^[10] +10^[x] +e^[x] 2) y=㏒ x +e^[x]+√x - 1/x-example-2
User N Kaushik
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9.2k points

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