Answer: Molarity of the solution is 0.813 M.
Step-by-step explanation:
Given : Mass of NaOH = 97.68 g
Volume of solution = 3 L
The molar mass of NaOH is 39.99 g/mol. Hence, moles of NaOH are calculated as follows.

Molarity is the number of moles of solute present in a liter of solution. Therefore, molarity of given solution is calculated as follows.

Thus, we can conclude that molarity of the solution is 0.813 M.