Question

g An airplane is flying through a thundercloud at a height of 1500 m. (This is a very dangerous thing to do because of updrafts, turbulence, and the possibility of electric discharge.) If a charge concentration of 25.0 C is above the plane at a height of 3000 m within the cloud and a charge concentration of -40.0 C is at height 850 m, what is the electric field at the aircraft

Answer 1

`523269.9\ \text{N/m}`

Step-by-step explanation:

q = Charge

r = Distance

`q_1=25\ \text{C}`

`r_1=3000\ \text{m}`

`q_2=40\ \text{C}`

`r_2=850\ \text{m}`

The electric field is given by

`E=E_1+E_1\\\Rightarrow E=k((q_1)/(r_1^2)+(q_2)/(r_2^2))\\\Rightarrow E=9* 10^9* ((25)/(3000^2)+(40)/(850^2))\\\Rightarrow E=523269.9\ \text{N/m}`

The electric field at the aircraft is
`523269.9\ \text{N/m}`