Answer:
a) v₂ = 30 m/s
b) m₁ = 12600 kg
c) m₂ = 12600 kg
Step-by-step explanation:
a)
Using the continuity equation:
![A_1v_1 = A_2v_2](https://img.qammunity.org/2022/formulas/physics/college/nmqjfdzkygscj80dutb57c5ucx12m2sa2z.png)
where,
A₁ = Area of inlet = π(0.15 m)² = 0.07 m²
A₂ = Area of outlet = π(0.05 m)² = 0.007 m²
v₁ = speed at inlet = 3 m/s
v₂ = speed at outlet = ?
Therefore,
![(0.07\ m^2)(3\ m/s)=(0.007\ m^2)v_2\\\\v_2 = (0.21\ m^3/s)/(0.007\ m^2)](https://img.qammunity.org/2022/formulas/physics/college/dvg93bkjm9rlmv6v1ziw772v2aqqve91ud.png)
v₂ = 30 m/s
b)
![m_1 = \rho A_1v_1t](https://img.qammunity.org/2022/formulas/physics/college/4lf97zfea6w9f0etgvq2i97r22q9vkq762.png)
where,
m₁ = mass of water flowing in = ?
ρ = density of water = 1000 kg/m³
t = time = 1 min = 60 s
Therefore,
![m_1 = (1000\ kg/m^3)(0.07\ m^2)(3\ m/s)(60\ s)\\](https://img.qammunity.org/2022/formulas/physics/college/c8lv9phvjrnpoj24eitsowx133stdha9c5.png)
m₁ = 12600 kg
c)
![m_1 = \rho A_1v_1t](https://img.qammunity.org/2022/formulas/physics/college/4lf97zfea6w9f0etgvq2i97r22q9vkq762.png)
where,
m₂ = mass of water flowing out = ?
ρ = density of water = 1000 kg/m³
t = time = 1 min = 60 s
Therefore,
![m_2 = (1000\ kg/m^3)(0.007\ m^2)(30\ m/s)(60\ s)\\](https://img.qammunity.org/2022/formulas/physics/college/edbwgx9jya58qmivvbv5c9av7v4q2ut1gw.png)
m₂ = 12600 kg