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Light with a wavelength of 700 nm (7×〖10〗^(-7) m) is incident upon a double slit with a separation of 0.30 mm (3 x 10-4 m). A screen is located 1.5 m from the double slit. At what distance from the screen will the first bright fringe beyond the center fringe appear?

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Answer:


0.0035\ \text{m}

Step-by-step explanation:

y = Distance from the center point

d = Separation between slits = 0.3 mm

D = Distance between slit and screen = 1.5 m


\lambda = Wavelength = 700 nm

m = Order = 1

We have the relation


d(y)/(D)=m\lambda\\\Rightarrow y=(Dm\lambda)/(d)\\\Rightarrow y=(1.5* 1* 700* 10^(-9))/(0.3* 10^(-3))\\\Rightarrow y=0.0035\ \text{m}

The distance from the screen at which the first bright fringe beyond the center fringe appear is
0.0035\ \text{m}.

User ManUtopiK
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