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A cylinder shaped water pitcher has a radius of 5 inches and a height of 12.5 inches find the surface area of the pitcher

A.5495 in² B. 54.95 in²
C.549.5 in² D. 5.495 in²​

2 Answers

5 votes

Question:-

A cylinder shaped water pitcher has a radius of 5 inches and a height of 12.5 inches. Find the surface area of the pitcher.

Answer:-

Given:-


\bullet Radius (r) of a cylinder shaped water pitcher = 5 inches.


\bullet Height (h) of a cylinder shaped water pitcher = 12.5 inches.

To Find:-

The surface area of the pitcher.

Solution:-

We know,

Formula of Surface area of a cylinder is 2πr(r + h) sq. units.

So,

Surface area of the pitcher = 2 × 3.14 × 5(5 + 12.5)

Surface area of the pitcher = 31.4 × 17.5

Surface area of the pitcher = 549.5 in²


\therefore The surface area of the pitcher is 549.5 in².

Hence, the option (C) 549.5 in² is correct. [Answer]

User Kamalpreet Grewal
by
4.1k points
2 votes

The surface area of the cylinder is 549.50 in².

What is the surface area of the cylinder?

A cylinder is a three-dimensional object. It is made up of a prism with a circular base. The total surface area is the sum of the areas of the faces or surfaces of a 3-dimensional object

Total surface area = 2πr(r + h)

Where:

  • π = 3.14
  • r = 5
  • h = height

2 x 3.14 x 5 (5 + 12.5) = 549.50 in²

User Collin Grady
by
4.2k points