Question

A sum of $104 is divided among three friends Adam, Charlie and Max in the ratio

3:4:6. How much more money does Max have than Adam?

Answer 1

Question:-

A sum of $104 is divided among three friends Adam, Charlie and Max in the ratio 3 : 4 : 6. How much more money does Max have than Adam ?

Solution:-

Ratio = 3 : 4 : 6 (Given)

`\bullet` Let the sum of Adam be 3x

`\bullet` Let the sum of Charlie be 4x

`\bullet` Let the sum of Max be 6x

`\therefore` Total sum = $104 (Given)

So,

ATQ ,

3x + 4x + 6x = 104

13x = 104

x =
`\bf (104)/(13)`

x = 8

Now, total sum of Adam = 3x = 3 × 8 = $24

Total sum of Max = 6x = 6 × 8 = $48

Required money Max have more than Adam = (48 - 24) = $24

$24 money does Max have more than Adam. [Answer]

Answer 2

$ 24

Explanation:

Ratio = 3 : 4 : 6

Amount with Adam = 3x

Amount with Charlie = 4x

Amount with Max = 6x

Total amount = $104

3x + 4 x + 6x = 104

13x = 104

x = 104/13

x = 8

Amount with Max = 6x = 6*8 = $ 48

Amount with Adam = 3x = 3 *8 = $ 24

Amount that is more with Max than Adam = 48 - 24 = $ 24