Answer:

Explanation:
Given
In a deck of card, we have:

![King[Heart] = 1](https://img.qammunity.org/2022/formulas/mathematics/college/eq8wse2qy0janqj24vamrrh4eanmvak2a3.png)
![Queen[Spade] = 1](https://img.qammunity.org/2022/formulas/mathematics/college/rdn1v47g9hsjvsa43ot0pfveenhx4s5xq0.png)
Required
The probability of obtaining a king of heart or a queen of spade.
The probability of king of heart is:
![P(King[Heart]) = (n(King[Heart]))/(Cards)](https://img.qammunity.org/2022/formulas/mathematics/college/i5obhigy7gcdt3jpaqf5rcwxosaeyjd5h5.png)
![P(King[Heart]) = (1)/(52)](https://img.qammunity.org/2022/formulas/mathematics/college/m4pj9gph4u686wl7uz391je68oazsbs2fq.png)
The probability of queen of spade is:
![P(Queen[Spade]) = (n(Queen[Spade]))/(Cards)](https://img.qammunity.org/2022/formulas/mathematics/college/l4qysrfb8w6aa8m0qmtx6ltiyfw3to03t9.png)
![P(Queen[Spade]) = (1)/(52)](https://img.qammunity.org/2022/formulas/mathematics/college/gtiolyahks38ywmipu4t5x6ubd3htite8p.png)
The required probability of obtaining a king of heart or a queen of spade. is:
![Pr = P(King[Heart]) + P(Queen[Spade])](https://img.qammunity.org/2022/formulas/mathematics/college/ntv12842r0kbecbd3r8wjbf49mc42iynlz.png)

Take LCM


Simplify
