1 Answer

Greatertomi · Answer 1 · 2022-06-05T12:12:52+0000

Given:

$P(A)=0.4, P(B)=0.7, P(A\text{ and }B)=0.3$

To find:

The value of
$P(A\text{ or }B)$ .

Solution:

We know that,

$P(A\text{ and }B)=P(A\cap B)$

$P(A\text{ or }B)=P(A\cup B)$

It means, we have
$P(A)=0.4, P(B)=0.7, P(A\cap B)=0.3$ and we need to find the value of
$P(A\cup B)$ .

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

$P(A\cup B)=0.4+0.7-0.3$

$P(A\cup B)=1.1-0.3$

$P(A\cup B)=0.8$

Therefore, the value of
$P(A\text{ or }B)$ is 0.8.

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