Determine the amplitude or period as requested. Period of y = - 1/3 * sin 2x

Question

asked Jun 24, 2022 24.4k views

1 Answer

Spacen Jasset · Answer 1 · 2022-07-01T02:02:48+0000

Answer:

$Period = \pi$

Explanation:

Given

$y = -(1)/(3) * \sin(2x)$

Required

The period

A sine function is represented as:

$y =A \sin(Bx + C) + D$

Where

$Period = (2\pi)/(B)$

By comparing:

$y =A \sin(Bx + C) + D$ and
$y = -(1)/(3) * \sin(2x)$

B = 2

So, we have:

$Period = (2\pi)/(2)$

$Period = \pi$

Hence, the period of the function is
$\pi$