Question

How many liters would you need to make a 0.8 M solution with 20 grams of lithium chloride?

Answer 1

0.5875L

Step-by-step explanation:

concentration = mole/ volume

n(LiCl) = 20 / (7 + 35.5) = 0.47 mol

volume = mole / conc.

volume = 0.47 /0.8

= 0.5875 dm³ = 0.5875L