Question

guys pls 3 :April and Bill went to the grocery store to buy chocolate bars. April bought 4 small chocolate bars and 6 large chocolate bars, while Bill bought 4 small chocolate bars and 3 large chocolate bars. If April paid $16.50 and Bill paid $11.25, what is the price of a single large chocolate bar?

Answer 1

To do this equation, we could put it in terms of algebra, lets say the large chocolate bars are represented by L and the small bars by S

April

4S + 6L = $16.50

Bill

4S + 3L = $11.25

Looking at this, we can see that the difference between the two purchases is that Bill bought three less large chocolate bars, this means the difference in total cost equals three large chocolate bars. Using this knowledge.

$16.50 minus $11.25 = $5.25

$5.25 = Three Large Bars

Divide this by three to get the cost of one large bar.

$1.75 is the cost of one single large bar.

Explanation:

credits to:

lolarodgers274

Answer 2

Cost of one large chocolate bar = $ 1.75

Explanation:

Let the cost of one small chocolate bars = $ s

Let the cost of one large bars = $ l

April:

Cost of 4 small bars = 4*s = 4s

Cost of 6 large bars = 6*l = 6l

Total cost of 4 small bars and 6 large bars = $ 16.50

4s + 6l = 16.50 ------------------(I)

Bill:

Cost of 4 small bars = 4*s = 4s

Cost of 3 large bars = 3*l = 3l

Total cost of 4 small bars and 3 large bars = $ 11.25

4s + 3l = 11.25 ------------------(II)

Subtract II form equation (I)

(I) 4s + 6l = 16.50

(II) 4s + 3l = 11.25 (-)

- - -

3l = 5.25 {Divide both sides by 3}

l = 5.25/3

l = 1.75

Cost of one large chocolate bar = $ 1.75