Answer:
0.668 atm
Step-by-step explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 0.715 atm
Initial temperature (T₁) = 30 °C
Final temperature (T₂) = 10 °C
Volume = constant
Final pressure (P₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 30 °C
Initial temperature (T₁) = 30 °C + 273
Initial temperature (T₁) = 303 K
Final temperature (T₂) = 10 °C
Final temperature (T₂) = 10 °C + 273
Final temperature (T₂) = 283 K
Finally, we shall determine the final. This can be obtained as follow:
Initial pressure (P₁) = 0.715 atm
Initial temperature (T₁) = 303 K
Final temperature (T₂) = 283 K
Final pressure (P₂) =?
P₁ / T₁ = P₂ / T₂
0.715 / 303 = P₂ / 283
Cross multiply
303 × P₂ = 0.715 × 283
303 × P₂ = 202.345
Divide both side by 303
P₂ = 202.345 / 303
P₂ = 0.668 atm
Thus, the final pressure of the hot air balloon is 0.668 atm