Question

Question 13

A hot air balloon has a pressure of 0.715 atm while the temperature outside is 30
degreeſ C. What will the pressure be if the temperature drops to 10 degrees C while
volume remains constant? Do not write units in the answer. Make sure to convert
temperature values to Kelvin.

Answer 1

0.668 atm

Step-by-step explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 0.715 atm

Initial temperature (T₁) = 30 °C

Final temperature (T₂) = 10 °C

Volume = constant

Final pressure (P₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 30 °C

Initial temperature (T₁) = 30 °C + 273

Initial temperature (T₁) = 303 K

Final temperature (T₂) = 10 °C

Final temperature (T₂) = 10 °C + 273

Final temperature (T₂) = 283 K

Finally, we shall determine the final. This can be obtained as follow:

Initial pressure (P₁) = 0.715 atm

Initial temperature (T₁) = 303 K

Final temperature (T₂) = 283 K

Final pressure (P₂) =?

P₁ / T₁ = P₂ / T₂

0.715 / 303 = P₂ / 283

Cross multiply

303 × P₂ = 0.715 × 283

303 × P₂ = 202.345

Divide both side by 303

P₂ = 202.345 / 303

P₂ = 0.668 atm

Thus, the final pressure of the hot air balloon is 0.668 atm