Question

B. Calculate the Pressure of 20.0 mole of helium in a 10.0 L cylinder at 273 K. [a = 0.0341 atm*L^2/mol^2 ; b = 0.0237L/mol ; R = 0.08205 L*atm/mol*K) *

87.3 atm
46.9 atm
55.5 atm
12 kPa

Answer 1

46.9 atm

Step-by-step explanation:

Applying Van der waals equation

P = [nRT/(V-nb)]- (an²/V²)............... Equation 1

Where P = pressure, T = temperature, n = number of moles, V = volume, R = Universal constant, a and b = gas constant

Given: n = 20 moles, R = 0.08205 L.atm/mol.K, T = 273 K, V = 10.0 L, a = 0.0341 atm.L²/mol², b = 0.0237L/mol

Substitute these values into equation 1

P = [(20×0.08205×273)/(10-20×0.0237)]-(0.0341×20²/10²)

P = (447.993/9.526)-0.1364

P = 47.028-0.1364

P = 46.9 atm