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What is the oxidation state of S in S2O32−?
A. +3 B. +2 C. –2 D. +4

1 Answer

4 votes

Answer:

it'd be +2

Step-by-step explanation:

Since 3 atoms of oxygen are present, so its combined oxidation number will be3(−2)=−6. Now this ion contains a charge of−2, where the sum of the oxidation number of all atoms in an atom is equal to−2. So the oxidation number of S in S2O2−3 should be +2.

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