Question

One number is 4 less than a second number. Twice the second number is 13 less than 5 times the first. Find the two numbers.

Answer 1

7 , 11

Explanation:

Let the second number be 'x'

the first number = x - 4

Twice the second number : 2*x = 2x

5times first = 5*(x -4) = 5*x - 5*4 = 5x - 20

13 less than 5 times the first = 5x - 20 - 13 = 5x - 33

5x - 33 = 2x

Add 33 to both sides

5x - 33 + 33 = 2x +33

5x = 2x + 33

Subtract '2x'from both sides

5x - 2x = 2x - 2x + 33

3x = 33

Divide both sides by 3

`(3x)/(3)=(33)/(3)`

x = 11

First number = x - 4 = 11 - 4 = 7

The numbers are 7 , 11