Question

What’s the surface area of a cone with the height of 50 and a radius of 40

Answer 1

the surface area of a cone: πr²+πLr

L = the slant height

r = radius of the base

r = 40 in : 2 = 20 in

L = 50 in

The surface area:

=π.20² + π.50.20

=1256+3140

=4396 in²