Question

The height in feet,h , of a model rocket t seconds after launch is given by the equation h(t) = 3+70t-16t^2.

Answer 1

If you're looking for the answer for edge, its;

B. The rocket is at a greater height when t = 3 than when t = 1.

Explanation:

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Answer 2

speed of the rocket is 6feet

Explanation:

Complete question

The height in feet, h, of a model rocket t seconds after launch is given by the equation h(t) = 3+70t - 16t^2. The average rate of change in h(t) between t = 1 second and t = 3 second is 6. What does the average rate of change tell you about the rocket?

Note that the average rate is also known as the speed

Average rate = h(3)-h(1)/3 - 1

h(3) = 3+70(3) - 16(3)^2

h(3) = 3 + 210 - 144

h(3) = 69

h(1) = 3+70(1) - 16(11)^2

h(1) = 3 + 70 - 16

h(1) = 73 -16

h(1) = 57

Average rate = 69-57/3-1

Average rate = 12/2

Average rate = 6ft/s

This shows that the speed of the rocket is 6feet