Question

- A closed container has a volume of 10 ml and a pressure inside of 20 P. If the

container is shrunk to 3 ml, what is the new pressure?

Answer 1

Answer: The new pressure is 66.66 mL.

Step-by-step explanation:

Given :
`V_(1)` = 10 mL,
`V_(2)` = 3 mL

`P_(1)` = 20 atm,
`P_(2) = ?`

Formula used to calculate the new pressure is as follows.

`P_(1)V_(1) = P_(2)V_(2)`

Substitute the given values into above formula as follows.

`P_(1)V_(1) = P_(2)V_(2)\\20 atm * 10 mL = P_(2) * 3 mL\\P_(2) = (20 atm * 10 mL)/(3 mL)\\= 66.66 mL`

Thus, we can conclude that the new pressure is 66.66 mL.