Answer:
prove that | S | = | E | ; every element of S there is an Image on E , while not every element on E has an image on S
Step-by-step explanation:
Given that S = p, q are prime numbers greater than 0
E = {0, −2, 2, −4, 4, −6, 6, · · · }
To prove by constructing a bijection from S to E
detailed solution attached below
After the bijection :
prove that | S | = | E | : every element of S there is an Image on E , while not every element on E has an image on S
∴ we can say sets E and S are infinite sets