Answer:
9. 4.8 Ω
10. 0.92 Ω
Step-by-step explanation:
9. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 Ω
Resistor 2 (R₂) = 20 Ω
Resistor 3 (R₃) = 30 Ω
Resistor 4 (R₄) = 40 Ω
Equivalent Resistance (R) =?
The equivalent resistance can be obtained as follow:
1/R = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄
1/R = 1/10 + 1/20 + 1/30 + 1/40
Find the least common multiple (lcm) of 10, 20, 30 and 40. The result is 120. Divide 120 by each of the denominator and multiply the result obtained by the numerator as shown below:
1/R = (12 + 6 + 4 + 3) / 120
1/R = 25 / 120
Invert
R = 120 / 25
R = 4.8 Ω
Thus, the equivalent resistance is 4.8 Ω
10. Determination of the equivalent resistance.
Resistor 1 (R₁) = 2 Ω
Resistor 2 (R₂) = 3 Ω
Resistor 3 (R₃) = 4 Ω
Equivalent Resistance (R) =?
The equivalent resistance can be obtained as follow:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/2 + 1/3 + 1/4
Find the least common multiple (lcm) of 2, 3 and 4. The result is 12. Divide 12 by each of the denominator and multiply the result obtained by the numerator as shown below:
1/R = (6 + 4 + 3) / 12
1/R = 13 / 12
Invert
R = 12 / 13
R = 0.92 Ω
Thus, the equivalent resistance is 0.92 Ω