What pressure will be needed to reduce the volume of 77.4 L of helium at 98.0kPa to a volume of 60.0L?

Question

asked Jun 9, 2022 234k views

1 Answer

Bill Mei · Answer 1 · 2022-06-15T16:57:27+0000

Answer:

Step-by-step explanation:

The final pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the final pressure

$P_2 = (P_1V_1)/(V_2) \\$

98 kPa = 98,000 Pa

We have

$P_2 = (98000 * 77.4)/(60) = (7585200)/(60) \\ = 126420$

We have the final answer as

Hope this helps you