Question

What pressure will be needed to reduce the volume of 77.4 L of helium at 98.0kPa to a volume of 60.0L?

Answer 1

126 kPa

Step-by-step explanation:

The final pressure can be found by using the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the final pressure

`P_2 = (P_1V_1)/(V_2) \\`

98 kPa = 98,000 Pa

We have

`P_2 = (98000 * 77.4)/(60) = (7585200)/(60) \\ = 126420`

We have the final answer as

126 kPa

Hope this helps you