Question

If I contain 2.5 moles of gas in a container with a volume of 45 liters and at a temperature of 261 K, what is the pressure inside the container in atmospheres?

Answer 1

The correct answer is "
`1.21* 10^5 \ Pa`".

Step-by-step explanation:

The given values are:

Number of moles,

n = 2.5 moles

Volume,

V = 45 liters

Temperature,

T = 261 K

As we know,

⇒
`PV=nRT`

or,

⇒
`P=(nRT)/(V)`

On substituting the values, we get

⇒
`=(2.5* 0.0821* 261)/(45)`

⇒
`=(53.57)/(45)`

⇒
`=1.19 \ atm`

On converting it in Pa, we get

⇒
`=1.19* 1.01325* 10^5`

⇒
`=1.21* 10^5 \ Pa`