Question

Adina has a total of $1.65 in nickels and dimes. The number of dimes is 6 more than the number of nickels. How many coins are there of each type?

Choose the correct system of equations needed to solve this problem.

A
0.10d+0.05n=60.10d+0.05n=60.10d+0.05n=6

n+d=1.65n+d=1.65n+d=1.65

B
d=n+6d=n+6d=n+6

0.05n+0.10d=1.650.05n+0.10d=1.650.05n+0.10d=1.65

C
n=d+6n=d+6n=d+6

0.10d+0.05n=1.650.10d+0.05n=1.650.10d+0.05n=1.65

D
n=d+6n=d+6n=d+6

0.05n+0.10d=1.650.05n+0.10d=1.650.05n+0.10d=1.65

Answer 1

C

Explanation:

If you divide 1.65 by 6 you'll get 0.275 so then you'll add d+6n to get d+6 and then you'll solve the question for 6n and you'll get 1.65