Question

What is the specific heat of ethanol if 4650 j are required to raise the temperature of 250.0g of ethanol from 22.0oc to 29.6 degrees Celsius

Answer 1

`C=2.45(J)/(g\°C)`

Step-by-step explanation:

Hello there!

In this case, since the thermodynamic definition of heat in terms of mass, specific heat and temperatures is given by:

`Q=mC(T_2-T_1)`

We are to calculate the specific heat of the ethanol as shown below:

`C=(Q)/(m(T_2-T_1))`

Thus, by plugging it the given data we can obtain:

`C=(4650J)/(250.0g(29.6-22.00\°C)) \\\\C=2.45(J)/(g\°C)`

Regards!