Question

A 0.582 mol sample of an ideal gas is at 15°C and 18.8 atm. Calculate the volume for this gas.

Answer 1

Answer: The volume for this gas is 0.732 L.

Step-by-step explanation:

Given : No. of moles = 0.582 mol

Temperature =
`15^(o)C = (15 + 273) K = 288 K`

Pressure = 18.8 atm

Using the ideal gas equation, volume for the given gas is calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula.

`PV = nRT\\18.8 atm * V = 0.582 mol * 0.0821 L atm/mol K * 288 K\\V = (0.582 mol * 0.0821 L atm/mol K * 288 K)/(18.8)\\= (13.761)/(18.8)\\= 0.732 L`

Therefore, it can be concluded that the volume for this gas is 0.732 L.