Question

Consider the reaction 2CO * O2 —> 2 CO2 what is the percent yield of carbon dioxide (MW= 44g/mol) of the reaction of 10g of carbon monoxide (MW=28g/mol) with the excess O2 produces 10g of carbon dioxide? Answer in units of %

Answer 1

Y = 62.5%

Step-by-step explanation:

Hello there!

In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:

`m_(CO_2)^(theoretical)=10gCO*(1molCO)/(28gCO)*(2molCO_2)/(2molCO) *(44gCO_2)/(1molCO_2)\\\\ m_(CO_2)^(theoretical)=16gCO_2`

Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:

`Y=(10g)/(16g) *100\%\\\\Y=62.5\%`

Best regards!