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Aaron invested $7,000 in an account paying an interest rate of 3\tfrac{5}{8}3 8 5 ​ % compounded continuously. Mia invested $7,000 in an account paying an interest rate of 3\tfrac{3}{4}3 4 3 ​ % compounded monthly. After 17 years, how much more money would Mia have in her account than Aaron, to the nearest dollar?

User Pavel Sem
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1 Answer

3 votes

Answer:

$265.27

Explanation:

Aaron invested $7,000 in an account paying an interest rate of 3 5/8 compounded continuously. Mia invested $7,000 in an account paying an interest rate of 3 3/4% compounded monthly. After 17 years , how much more money would Mia have in her account than aaron, to the nearest dollar?

Aaron:

A = Pe^rt

r = 3 5/8%

r = 3.625/100

r = 0.03625 rate per year

A = Pe^rt

A = 7,000(2.71828)^(0.03625)(17)

= 7,000(2.71828)^0.61625

= 7,000(1.8519693482716)

A = $12,963.79

Mia:

A = P(1 + r/n)^nt

r = 3 3/4%

r = 3.75/100

r = 0.0375 rate per year

A = P(1 + r/n)^nt

A = 7,000(1 + 0.0375/12)^(12)(17)

A = 7,000(1 + 0.003125)^(204)

A = 7,000(1.003125)^204

A = 7,000(1.8898660935607)

A = $13,229.06

Difference between Mia and Aaron account

Mia - Aaron = $13,229.06 - $12,963.79

= $265.27

User Spike Williams
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