Question

3 times a number is 10 less than the square of that number find the negative solution

Answer 1

- 2

Explanation:

let the number be n then 10 less than the square is n² - 10 and equating

n² - 10 = 3n ( subtract 3n from both sides )

n² - 3n - 10 = 0 ← in standard form

(n - 5)(n + 2) = 0 ← in factored form

Equate each factor to zero and solve for n

n - 5 = 0 ⇒ n = 5

n + 2 = 0 ⇒ n = - 2

The negative solution is - 2