Answer:
d
Explanation:
Δ OPG is right with hypotenuse OG being the radius of the circle
Using Pythagoras' identity in the right triangle
OG² = OP² + PG²
[ PG = 11 , since OP is the perpendicular bisector of FG ]
OG² = 8² + 11² = 64 + 121 = 185
Δ OQS is right with hypotenuse OS being the radius
Using Pythagoras' identity
OS² = QS² + OQ² , that is
185 = 13² + x²
185 = 169 + x² ( subtract 169 from both sides )
16 = x² ( take the square root of both sides )
4 = x → d