Answer:
Option C - 1 mole
Step-by-step explanation
a) no of moles of solute = 4.1×0.05
moles = O.205
so the mass of of sodium chloride present is 0.205×58.44
Mass of NaCl = 11.98 g
b) no of moles of solute = 1.8×0.01= 0.018
so the mass of of sodium chloride present is 0.018×58.44
Mass of NaCl = 1.05g
C) number of moles of solute is 1 mole
mass of solute is =58.44g
d) mass =9.35g
So the conclusion is that 1 mole is the correct answer!!!!