Question

6. A balloon filled with air has a volume of 3.25 L at 30°C. It is placed in a freezer at

-10°C. What is the volume of the balloon at this temperature? Assume that the pressure is
constant. What are the temperatures in Kelvin? Should v. be bigger or smaller?

Answer 1

2.82 L

T₁ = 303 K

T₂ = 263 K

The final volume is smaller.

Step-by-step explanation:

Step 1: Given data

• Initial temperature (T₁): 30 °C

• Initial volume (V₁): 3.25 L

• Final temperature (T₂): -10 °C

• Final volume (V₂): ?

Step 2: Convert the temperatures to Kelvin

We will use the following expression.

K = °C + 273.15

T₁: K = 30°C + 273.15 = 303 K

T₂: K = -10°C + 273.15 = 263 K

Step 3: Calculate the final volume of the balloon

Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 3.25 L × 263 K/303 K = 2.82 L